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2024 Paper 2, Q19

6 marks Technology-active Engine: provided tool
The question, as it appeared

The normal distribution probability density function is

$$p(x)=\frac{1}{\sigma\sqrt{2\pi}}e^{-\frac12\left(\frac{x-\mu}{\sigma}\right)^2}$$

with the parameters mean, $\mu$, and standard deviation, $\sigma$.

The speeds of electric scooter (e-scooter) riders on a particular section of a bike path are approximately normally distributed with a mean of 18 km/h. It is known that $p(10)=0.0135$.

The speed limit for e-scooters on this section of bike path is 23 km/h. A speed camera is set up and records the speeds of 75 e-scooter riders. Every rider travelling faster than the speed limit is given a $\$143$ fine. Before setting up the speed camera, the following suggestion was made.

The total of the fines expected to be issued will be more than $\$1500$.

Evaluate the reasonableness of this suggestion.

Watch the situation first

Seventy-five riders go past one speed camera

Most riders sit near 18 km/h. Only the right-hand tail gets fined, and a tail that thin cannot pay for the claim.

23 km/h limit 18 23 28 speed (km/h) $1133 expected $1500 claimed 75 riders, centred on 18 km/h about 8 of them break the limit 8 × $143 falls $367 short of the claim
The insight marks

The density formula is there to be solved, not just substituted into

One equation, one unknown

$p(10)=0.0135$ with $\mu=18$ leaves $\sigma$ as the only unknown. Substitute and solve on the GDC. There is nothing to differentiate or integrate.

Two answers come back

$\sigma=4.0002$ and $\sigma=28.4020$ both satisfy it. One of them has to be rejected on physical grounds. And that rejection is worth a mark.

Then three ordinary steps

$P(X>23)$, times 75 riders, times $\$143$. The unfamiliar part is over as soon as $\sigma$ is known.

The chain $0.0135\ \rightarrow\ \sigma=4\ \rightarrow\ P(X>23)=0.1057\ \rightarrow\ 7.92\ \text{riders}\ \rightarrow\ \$1133$
Now for the mathematics

Hunt for the σ that makes p(10) = 0.0135

Drag $\sigma$. The height of the curve at $x=10$ rises, peaks and falls again. Which is exactly why the equation has two roots. Both are marked on the right.

The density, with your σ
10 18 23 speed (km/h) fined
p(10) as σ changes
two values of σ give 0.0135
0.0135 4.0 28.4 σ (km/h) the peak sits between them
p(10)
target 0.0135
Riders fined
P(X > 23) =
Expected fines
Before you read the solution

Why is $\sigma=28.4$ rejected?

QCAA marking guide

QCAA marking guide · 6 marks

Step 1 · substitute into the given formula
1 mark

$$0.0135=\frac{1}{\sigma\sqrt{2\pi}}e^{-\frac12\left(\frac{10-18}{\sigma}\right)^2}$$

Marker: correctly substitutes the known information, $x=10$ and $p(10)=0.0135$, into the given normal distribution formula.

Step 2 · solve, and throw one root away
1 mark

Using a GDC, you get two solutions, $\sigma=4.0002$ and $\sigma=28.4020$.

Reject 28.4020: three standard deviations below the mean would be a negative speed, and three above would be over 100 km/h on an e-scooter.

Marker: determines a possible value for the standard deviation. FT marks allowed for errors in prior working.

Step 3 · the tail above the limit
1 mark

$$X\sim N(18,4.00^2):\quad P(X\ge 23)=0.10566$$

Marker: determines the proportion of riders above 23 km/h. Appropriate rounding accepted, e.g. 0.106 or 0.11.

Step 4 · how many riders
1 mark

$$75\times 0.10566=7.92\ \text{riders}$$

Marker: determines the number of riders above 23 km/h. The decimal is accepted, and so is rounding to 7 or 8, and the later marks then follow from whichever you chose.

Step 5 · the money
1 mark

$$7.9245\times 143=\$1133.20$$

Marker: determines the expected total fines. Equivalent totals accepted for a rounded rider count, e.g. $8\times\$143=\$1144$ or $7\times\$143=\$1001$.

Step 6 · answer the claim
1 mark

About $1133, which is less than $1500,,,, so the suggestion is not reasonable

Marker: provides an appropriate statement of reasonableness. This mark can only be awarded if previous evidence supports the conclusion. The sentence has to name the two numbers it compares.

Putting it all together

The rejected root would have changed the verdict

With σ = 4

$1133 · not reasonable

10.5 riders would have to be fined to reach $1500. The tail only supplies 7.9.

With σ = 28.4

$4600 · reasonable

Keeping the wrong root reverses the conclusion, which is why the rejection is a marked step and not a formality.

Why σ = 4 is exact

At $\sigma=4$, $x=10$ is exactly two standard deviations out, so $p(10)=\frac{e^{-2}}{4\sqrt{2\pi}}=0.013499$. The paper chose 0.0135 to make the root land on a whole number.

What makes this complex unfamiliar

The QCAA print the density function at the top of the question, and that is what makes it tricky. You are used to areas under the normal curve, not the height of it, so it is natural to ignore the formula and look for a probability instead. Here the height is the only way to find $\sigma$. This is a provided tool, because the formula is not something the syllabus asks you to know. Your calculator then gives you two roots, and there is a mark for choosing the right one. A standard deviation of 28 km/h around a mean of 18 km/h would put a quarter of the riders at a negative speed, which makes no sense. The rest is familiar, but the marker expects every step. Find the proportion, then the number of riders, then the money, then write your sentence. I see a lot of marks lost at that final sentence.

Keep going

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Question wording and marking-guide steps are from the 2024 QCAA Mathematical Methods external assessment, © State of Queensland (QCAA) 2024, licensed under CC BY 4.0, and have been adapted. Tangent Tuition is not affiliated with the QCAA.